Determine the required height h of the roller coaster so that when it is essentially at rest at the crest of the hill A it will reach a speed of 100km/h when it comes to the bottom B. Also, what should be the minimum radius of curvature p for the track at B so that the passengers do not experience a normal force greater than 4mg

a) 39.37 m

b) 26.25 m

Explanation:

Given

speed of the roller coaster, v = 100 km/h = 100 * (1000/3600) m/s = 27.78 m/s

Using the law of conservation of energy.

Potential Energy = Kinetic Energy

mgh = 1/2mv²

gh = 1/2v²

h = v²/2g

h = 27.78² / 2 * 9.8

h = 771.7284 / 19.6

h = 39.37 m

Also,

kmg - mg = mv²/p

kg - g = v²/p

p = v²/g(k - 1)

p = 27.78² / 9.8(4 - 1)

p = 771.7284 / 29.4

p = 26.25 m

Therefore, the height of the roller coaster is 39.37 m and the radius of curvature required is 26.25 m

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees. 

f=ma newton's second law 7x8=56n