23. Two slits are separated by 0.180 mm. An interference pattern is formed on a screen 80.0 cm away by 656.3-nm light.
Calculate the fraction of the maximum intensity a distance y 5 0.600 cm away from the central maximum.

The fraction of the maximum intensity a distance y 5 0.600 cm away from the central maximum is 0.97.

Explanation:

d = 0.180 mm = 1.8 x 10⁻⁴ m

L = 80 cm = 0.8 m

λ = 656.3 nm = 6.563 x 10⁻⁷ m

y = 0.6 cm = 6 x 10⁻³ m

we know that the equation of the intensity for two slits interference equation is

I = cos²(πdy/λL)

where

I = intensity

 = maximum intensity

d = distance of two slits

y = the distance of the interference with the central

L = the distance of screen and the slits

λ = wavelength

so,

I = cos²(πdy/λL)

I/  = cos²(πdy/λL)

          = cos²[π (1.8 x 10⁻⁴) (6 x 10⁻³)/(6.563 x 10⁻⁷) (0.8 )]

          = 0.97

answer: point c: b. 1/2 potential, 1/2 kinetic, point a: 3/4 of its potential energy, point d or b: 3/4 potential, 1/4 kinetic

explanation: i cant explain. it's difficult to explain.

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be