An electron that is moving to the right experiences a magnetic field of 2.5 T directed upward. If the force on the electron is 2.4 x 10^-12N, what is the speed of the electron?

5.99×10⁶ m/s

Explanation:

We look for the speed of the electron by applying,

F = Bqv Equation 1

Where F = Force on the electron, B = magnetic field, q = charge of an electron, v = speed of the electron.

make v the subject of the equation

v = F/Bq Equation 2

Given: F = 2.4×10⁻¹² N, B = 2.5 T.

Constant: q = 1.602×10⁻¹⁹ C

Substitute into equation 2

v = 2.4×10⁻¹² /(2.5× 1.602×10⁻¹⁹ )

v = 5.99×10⁶ m/s

d they tend to lose electrons and become cations.

explanation: