A mass m = 3.9 kg hangs from a massless string wrapped around a uniform cylinder with mass Mp = 10.53 and radius R= 0.96 m. The cylinder has a frictionless pivot in the center. The mass is released from rest and falls downwards unwinding the string from the outside of the cylinder.

What is the rotational inertia of the cylinder, and how fast is the mass moving after it has fallen a distance of 7.56 m.?

the rotational inertia of the cylinder = 4.85 kgm²

the mass moved 7.942 m/s

Explanation:

Formula for calculating Inertia can be expressed as:

For calculating the rotational inertia of the cylinder ; we have;

I ≅ 4.85 kgm²

mg - T ma and RT = I ∝

T =

a = 4.1713 m/s²

Using the equation of motion

you cant move and you feel like someones pushing you down onto your bed it can feel like you want to get up but you just can't it can be extremely scary

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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