What will be the primary voltage of a transformer if the secondary voltage is 60 V and there are 40 loops on the primary coil and 120 loops on the secondary coil?

20 V

Explanation:

We can solve this problem by applying the transformer formula:

V(out) / V(in) = Ns / Np

Where V(out) = voltage at the secondary coil

V(in) = voltage at the primary coil

Ns = number of loops in the secondary coil

Np = number of loops in the primary coil

From the question:

V(out) = 60 V

Ns = 120

Np = 40

We need to find V(in)

V(in) = V(out) * Np / Ns

V(in) = (60 * 40) / 120

V(in) = 20 V

The voltage in the primary coil (primary voltage) is 20 V

r=rho l/a where a is the area, l is the length and rho is resistivity so the greater the area the lesser the resistance thats why the earth pin is thicker bcos current follow the shortest path, so less resistive .

where’s the list ? the question is incomplete