A ray of light is incident on the surface of a block of clear ice at an angle of 39.0° with the normal. Part of the light is reflected and part is refracted. Find the angle between the reflected and refracted light.

112.76°

Explanation:

The angle of the reflected light is the same as the angle of the incident light:

The refracted angle is obtained by using the Snell's law:

n1: air index of refraction ≈ 1.00

n2: ice index of refraction = 1.31

By replacing the values for the incident angle and the index of refraction you can calculate the angle of refraction:

the angle between the reflected and refracted angle will be:

where you have taken into account that the angles aremeasured according to the horizontal axis.

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c. magnitude and direction