Question 5
An instrument plays a frequency of 266 Hz. Another identical instrument plays a frequency of 400 Hz. How do the wavelength of each of these
sound waves compare?

the wavelength of the first instrument is approximately 1.5 greater than that produced by the second instrument.

Explanation:

Given:

f₁ = frequency = 266 Hz

f₂ = 400 Hz

Question: How do the wavelength of each of these sound waves compare, λ₁ = ?, λ₂ = ?

The equation to solve this question is

Here

λ = wavelength of the sound

v = speed of sound = 340 m/s

f = frequency of each instrument

You need to calculate both wavelengths

According to the results, the wavelength of the first instrument is approximately 1.5 greater than that produced by the second instrument.

c. convergent boundary.

explanation:

c) power lifting, will be your answer.

,

deku ❤