An object is moving at a velocity of 30m/s. It accelerations to a velocity of 55m/s over a time of 12.5 m/s. What acceleration did it experience?

Acceleration = (change of speed) / (time for the change)

Change of speed = (speed at the end) - (speed at the beginning)

Change of speed = (55 m/s) - (30 m/s)

Change of speed = 25 m/s

Acceleration = (25 m/s) / (12.5 seconds)

Acceleration = 2 m/s²

2m/s^2

Explanation:

Initial velocity(u)=30m/s

Final velocity(v)=55m/s

Time(t)=12.5s

Acceleration=?

Acceleration=(v-u)/t

Acceleration=(55-30)/12.5

Acceleration=25/12.5

Acceleration=2m/s^2

a small object of mass 3.66 g and charge -17.6 µc is suspended motionless above the ground when immersed in a uniform electric field perpendicular to the ground. what are the magnitude and direction of the electric field?

d eras and periods