An object is traveling at a constant velocity of 12 m/s when it experiences a constant acceleration of 2.5 m/s2 for a time of 20s. What will its velocity be after that acceleration?

62m/s

Explanation:

Initial velocity(u) =12m/s

Acceleration(a)=2.5m/s2

Time(t)=20seconds

Final velocity(v)=?

V=u+axt

V=12+2.5x20

V=12+50

V=62m/s

a) electrical > light, sound, and thermal< < < <

) the mechanical energy of the firefighter moving.< < < < a) electrical > light, sound, and thermal< < < <

c) both a and b.

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j