Physics! Someone help me! Its due today please!

Assume a 9.0 kg bowling ball moving at 5 m/s bounces off a spring at 2 m/s.

(a) What is its change in velocity of the bowling ball?

(b) What is its change of momentum of the ball?

(c) What is the impulse exerted on of the ball?

(d) If the interaction with the spring occurs in 0.3 s, calculate the average force the spring exerts on the ball.

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.