In a test run, a certain car accelerates uniformly from zero to 24.0 m/s in 2.95 s. (a) what is the magnitude of the car’s acceleration? (b) how long does it take the car to change its speed from 10.0 m/s to 20.0 m/s? (c) will doubling the time always double the change in speed? why?

(a) 8.14 m/s^2

Explanation:

Acceleration of the car is given by:

where

u = 0 is the initial velocity

v = 24.0 m/s is the final velocity

t = 2.95 s is the time taken

Substituting numbers into the equation, we find

(b) 1.23 s

Explanation:

We can use the same formula for the acceleration:

where this time, we have

u = 10.0 m/s

v = 20.0 m/s

a = 8.14 m/s^2

Substituting numbers into the equation, we can find the time taken, t:

c) If the acceleration is constant, yes

Explanation:

Let's take again the equation for the acceleration:

We can rewrite it as:

where the term (v-u) represents the change in velocity. From the formula we see that, if a (acceleration) is constant, then (v-u) is directly proportional to the time t: therefore, if t doubles, the change in velocity (v-u) doubles as well.

d. platinum would have the greatest temperature increase because it has the lowest specific heat.

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