An electron is confined in a harmonic oscillator potential well. A photon is emitted when the electron undergoes a 3→1 quantum jump. What is the wavelength of the emission if the net force on the electron behaves as though it has a spring constant of 3.6 N/m? (m el = 9.11 × 10-31 kg, c = 3.00 × 108 m/s, 1 eV = 1.60 × 10-19 J, ħ = 1.055 × 10-34 J · s, h = 6.626 × 10-34 J · s)

4.74*10^-7 m

Explanation:

TO find the wavelength of the photon you calculate the energy of the photon emitted in a harmonic oscillator:

m: initial state = 3

n: final state = 1

k = 3.6N/m

By replacing the values of m for the electron, m,n and ħ you obtain:

Furthermore, this energy is equivalent to the expression:

By replacing you obtain:

hence, the wavelength of the photon is 4.74*10^-7 m

magnityde and direction

object 2 because all the other ones are wrong