Two lasers are shining on a double slit, with slit separation d. Laser 1 has a wavelength of d/20, whereas laser 2 has a wavelength of d/15. The lasers produce separate interference patterns on a screen a distance 4.80m away from the slits.

Part A

Which laser has its first maximum closer to the central maximum?

Part B

What is the distance \Delta _y__max-max_ between the first maxima (on the same side of the central maximum) of the two patterns?

Express your answer in meters.

Part C

What is the distance \Delta _y__max-max_ between the second maximum of laser 1 and the third minimum of laser 2, on the same side of the central maximum?

Express your answer in meters.

A) first laser

B) 0.08m

C) 0.64m

Explanation:

To find the position of the maximum you use the following formula:

m: order of the maximum

λ: wavelength

D: distance to the screen = 4.80m

d: distance between slits

A) for the first laser you use:

for the second laser:

hence, the first maximum of the first laser is closer to the central maximum.

B) The difference between the first maximum:

hence, the distance between the first maximum is 0.08m

C) you calculate the second maximum of laser 1:

and for the third minimum of laser 2:

Finally, you take the difference:

hence, the distance is 0.64m

the duration of a photographic flash is related to an rc time constant, which is 0.100 μs for a certain camera.