Copper wire #1 has a length L and a radius b. Copper wire #2 has a length 2L and a radius 2b. Which statement about the resistance across the ends of the wires is true? The resistance of wire #1 is four times higher than that of wire #2. The resistance of wire #1 is equal to that of wire #2. The resistance of wire #1 is twice as high as that of wire #2. The resistance of wire #1 is half that of wire #2.

The resistance of wire #1 is twice as high as that of wire

Explanation:

For resistance of a wire the formula is as follows

R = ρ l / s where  ρ is a constant called specific resistance , l is length and s is cross sectional area . If r be the radius of cross section

R = ρ l / π r²

For first wire , putting the given values in the equation

R₁ = ρ L/ π b²

For second wire,

R₂ = ρ 2L/ π 4b²

= 2

The resistance of wire #1 is twice as high as that of wire

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has mass of one amu