A sled on ice moves in the ways described in questions 1-7 below. Friction is so small that it can be ignored. A person wearing spiked shoes standing on the ice can apply a force to the sled and push it along the ice. Choose the one force (A through G) which would keep the sled moving as described in each statement below. You may use a choice more than once or not at all but choose only one answer for each blank.
A. The force is toward the right and is decreasing in strength (magnitude).
B. The force is toward the right and is increasing in strength (magnitude).
C. The force is toward the right and is of constant strength (magnitude).
D. The force is toward the left and is decreasing in strength (magnitude).
E. The force is toward the left and is increasing in strength (magnitude).
F. The force is toward the left and is of constant strength (magnitude).
G. No applied force is needed.

Check Explanation.

Explanation:

(1). The force that will continue to move the sled toward the right and speeding up at steady rate(constant acceleration) = option C => The force is toward the right and is constant strength (magnitude).

(2). The force that will continue to move the sled toward the right and at Constant velocity = option G => No applied force is needed. This is because acceleration = 0,and force is also = 0.

(3). The force that will continue to move at steady rate and an acceleration to the right = option A => The force is toward the right and is decreasing in strength (magnitude).

(4). The force that will slow the sled moving to the right at steady rate(constant acceleration) = option F => The force is toward the left and is of constant strength (magnitude).

(5). The force that moves the sled rest toward the a steady (velocity) towards the left = option G => No applied force is needed.

i don't understand. explain it clearly

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y