A car is going 60.0 mi/h and has to stop in 6.0 seconds. What is the car’s acceleration?

Explanation:

Convert mi/h to ft/s.

60.0 mi/h × (5280 ft/mi) × (1 h / 3600 s) = 88.0 ft/s

Find the acceleration.

a = Δv / Δt

a = (0 ft/s − 88.0 ft/s) / 6.0 s

a = -14.7 ft/s²

The driver must accelerate the car at the average rate of

- 10 mile / hour-second

for 6 seconds .

the answer is 12 as i may remember

: )

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y