Write a nuclear equation to describe the neutron induced fission of u-235 to form xe-134 and sr-100. Determine how many neutrons are produced in the reaction.

The nuclear equation is give as

The number of neutrons produced = 2

Explanation:

Since the reaction is a neutron induced fission of Uranium, a certain amount of neutron will be emitted with Xe - 34 and Sr - 100

Therefore the nuclear equation is given as:

To get the value of y:

Sum of mass numbers at the reactant = Sum of mass numbers at the product

235 + 1 = 134 + 100 + y

y = 236 - 234

y = 2

Therefore, the nuclear equation above becomes:

As seen from the equation above, the number of neutrons produced in the reaction = 2

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0 = 0.40 / 0 = 0

= 0.20 = 9.80 ⁄2 =?

=0 , = = 0.20 =0.50 0 0.40 ⁄

=0−122 =0−12(9.80 ⁄2)(0.50)2 =1.2