Objects 1 and 2 attract each other with a electrostatic force of 72.0 units. if the charge of object 1 is doubled and the distance separating objects 1 and 2 is doubled , then the net electrostatic force will be ?

Ithink the answer is c but then again i'm probably wrong

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

The sunlight shines uv radiation on earth,a microwave oven radiates waves on food