A ball is thrown straight up with an initial velocity of 50 m/s.
a) How high will it go?
b) How long does it take to reach this height?

a.) Maximum height = 127.4 metre

b.) Time = 5.1 seconds

Explanation:

Given that initial velocity U = 50m/s

a.) How high will it go means maximum height.

At maximum height, final velocity V = 0

Using the equation 3 of linear motion

V^2 = U^2 - 2gH

As the ball is going up, g will be negative.

0 = 50^2 - 2 × 9.81H

2500 = 19.62H

H = 2500/19.62

H = 127.4 meters

b.) The time taken to reach the maximum height

Using the 2nd equation of motion

h = Ut + 1/2gt^2

127.4 = 50t - 1/2 × 9.8t^2

127.4 = 50t - 4.9t^2

4.9t^2 - 50t + 127.4 = 0

This will lead to quadratic equation

Where a = 4.9, b = -50, c = 127.4

Using quadratic formula will lead to

50 +/- root ( 50^2 - 4 × 4.9 × 127.4)/2 × 4.9

50 +/- root ( 2500 - 2497.04)/9.8

50+/- root( 2.96)/9.8

50+/- 1.72/9.8

(50 + 1.72)/9.8 or (50 - 1.72)/9.8

51.72/9.8 = 5.28s

Or 48.28/9.8 = 4.9s

To test for this let's assume it's a perfect parabola. Using vertex formula,

t = -b/2a

t = 50/9.8

t = 5.1 m/s

answer;

d. are made mostly of liquid

explanation;

-the general   composition and structure planets includes; they have a thick gas and liquid layer covering a small,solid core. mostly the gases are hydrogen and helium atmosphere and layers of liquid hydrogen. for instance neptune and uranus are examples of the outer planets, they have a core covered by ice and ammonia.

-neptune's atmosphere is hydrogen and helium with a bit of methane so there is no oxygen to breath and the interior is made up of frozen water and ammonia with a rock and iron core. thus, there is no liquid water or solid surface to survive.

the ima (higher than 1m) will be greater than the ima with the height of 1m.