An inclined plane of length 10m has a height of 6m. If the coefficient of friction between the block and the plane is 0.4. a. What force parallel to the plane is needed to slide the 50 kg block up the plane with a uniform speed ? b. What is the efficiency of the plane

F = 489.93 N

Explanation:

I attached an image of the system below.

By using a rotated system of coordinates you have the following equation:

 (1)

F: force

Ff: friction force

Wx: x component of the weight = Wxsin(θ)

In this case you have that the speed of the block is constant, then a= 0m/s^2.

You also consider that the friction force is given by:

Wx = μNsin(θ) = μmgsin(θ)

μ: friction coefficient = 0.4

m: mass of the block = 50kg

g: gravitaional acceleration = 9.8m/s^2

θ is the angle of inclination of the inclined plane, you calculate this by using the following:

You replace the values of the parameters in the equation (1) with a = 0m/s^2

freezing

deposition

condensation

explanation;

melting also called fusion is the process where solid becomes liquid, sublimation is the process where solid becomes gaseous without first changing to liquid, deposition involves change from gaseous to solid state, freezing involves change from liquid to solid, boiling or evaporation involves change of liquid to gaseous state, while condensation is the change from gaseous state to liquid state.

endothermic reactions involves absorption of heat from the surroundings or the environment while exothermic reactions involves loss of heat energy to the surroundings.

in this case, sublimation, evaporation and melting are endothermic reactions (gain energy from the environment) while, freezing, deposition and condensation are exothermic (loss of energy to the surroundings) reactions.

v 154.9= 0.9 length length s little over 154.9cm