Find the total capacitance for three capacitors connected in series, given their individual
capacitances are 1.0 F, 5.0 F, and 8.0 F.

0.75F

When capacitors are connected in series, the reciprocal of their total capacitance is the sum of the reciprocals of their individual capacitances. In other words, when, say, three capacitors, C₁, C₂ and C₃ are connected in series, their total capacitance, C, is given by;

= + +  -------------------(i)

Now to solve the question,

Let;

C₁ = 1.0F

C₂ = 5.0F

C₃ = 8.0F

Substitute these values into equation (i) as follows;

= + +

Solve for C

=

=

C =

C = 0.75

Therefore, their total capacitance is 0.75F

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

b. lifting dumbbell weight at 20-degree angle from the body after a 45-degree angle