The friends now feel prepared for a homework problem. Consider a cylinder initially filled with 9.30 10-4 m3 of ideal gas at atmospheric pressure. An external force is applied to slowly compress the gas at constant temperature to 1/6 of its initial volume. Calculate the work that is done. Note that atmospheric pressure is 1.013 105 Pa

Explanation:

Initial volume of gas V₁ = 9.30 x 10⁻⁴ m³

final volume V₂ = 1 / 6 x  9.30 x 10⁻⁴

= 1.55 x 10⁻⁴ m³

Atmospheric pressure P = 1.013 x 10⁵ Pa .

temperature T .

PV = n RT

nRT = 1.013 x 10⁵ x 9.3 x 10⁻⁴

= 94.21

work done in isothermal process

= 2.303 nRT log V₁ / V₂

= 2.303 x 94.21 log 6

= 168.83 J .

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