Q2: The RMS potential difference of an AC household outlet is 117 v.
a) What is the maximum potential difference across a lamp connected to the outlet?
b) If the RMS current through the lamp is 5.5 A, what is the lamp's maximum current?

(a) 165.46 V

(b) 7.78 A

Explanation:

(a) From the question,

Vrms = V₀/√2 Equation 1

Where V₀ = maximum potential difference across a lamp connected to the outlet.

make V₀ the subject of the equation.

V₀ = √2(Vrms) Equation 2

Given: Vrms = 117 V.

Substitute into equation 2

V₀ = (√2)(117)

V₀ = 165.46 V.

(b) Similarly,

I₀ = √2(Irms) Equation 3

Given: Irms = 5.5 A

Substitute into equation 3

I₀ = (√2)(5.5)

I₀ = 7.78 A.

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

the gas collects in coils that then becomes a liquid that then flows through the coils inside the refrigerator