The left end of a long glass rod 9.00 cm in diameter, with an index of refraction 1.61, is ground and polished to a convex hemispherical surface with a radius of 4.50 cm. An object in the form of an arrow 1.55 mm tall, at right angles to the axis of the rod, is located on the axis 24.0 cm to the left of the vertex of the convex surface.(a) Find the position of the image of the arrow formed by paraxial rays incident on the convex surface.(b) Find the height of the image formed by paraxial rays incident on the convex surface.(c) Is the image erect or inverted?

a) 17.15cm

b)0.687mm

c)erect

Explanation:

Given:

Diameter = 9.00 cm

for air =1

Index of refraction n₂= 1.61

Radius of curvature R= 4.50

Height of object h₀= 1.55 mm

Object distance u= 24.0 cm

(A)In order to calculate the image distance , we use formula for image of distance

By plugging in all the required values

(B). In order to calculate the height of the image , we'll use formula of magnification

By substituting all the required values, we get

c) The image is erect as it is of (+)ve sign.

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force