If a 0.5 kg ball is thrown up with 250 J of kinetic energy, how high will it go? (HINT: At the ball's highest point it has stopped.)
KE = 1/2mv2
G = 9.8 m/s2

51.02m

Explanation:

KE = 1/2mv2

Where k.e = 250J

mass = 0.5 kg

g = 9.8 m/s2

250= 1/2×0.5×v^2

250= 0.5×0.5×v^2

250= 0.25v^2

v^2 = 250/0.25

v^2 = 1000

v =√1000

v = 31.62m/s

v^2= u^2-2gh (1)

Since the object will stop at it highest point, hence it final velocity there will be zero and since it is moving up against the gravity g= -9.8m/s^2. That was why the formula in equation 1 has a negative sign

From h = u^2/2g

Where v = 31.62m/s

g = 9.8m/s^2

H = (31.62m/s)^2/9.8×2

H= 1000/19.6

= 51.02m

Hence the height of it travelling will be

51.02m

electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia

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