Por una espira de 0.5 m2 de área circula una corriente de 5 A. Calcula la densi- dad de flujo magnético B considerando que la espira considera la permeabilidad del medio es la del aire

Explanation:

The density of the magnetic flux is given by the following formula:

The normal vector A and the vector of the magnitude of the magnetic field are perpendicular, then, the angle is zero:

The magnitude of the magnetic field is calculated by using the formula for B at a distance of x to a point in the plane of the loop:

For x = 0 you have:

R is the radius of the circular loop and its values is:

Then, you replace in the equation for B with mu_o = 4\pi*10^-7 T/A:

and the density of the magnetic flux is

the answer is kevlar

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