A bungee cord is attached to a wagon and is used to pull a child while you take her for a ride. The bungee’s original unstretched length is 1.3 m. The girl weighs 220 N, and the wagon weighs 75 N. You accelerate from rest to your normal walking speed of 1.5 m/s in 2 seconds, and you notice that while you are accelerating, the bungee’s length increases to about 2 m. What is the force constant of the bungee cord, assuming it obeys Hooke’s law?

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

Answertechnician (a) is correct;

Bis the answerhope it !