A positive test charge of 5.0 x 10^-4 C is in an electric field that exerts a force of 2.5 x 10^-4 N on it. What is the magnitude of the electric field at the location of the test charge?

E = 0.5N/C

Explanation:

In order to calculate the magnitude of the electric field you use the following formula:

q: charge = 5.0*10^-4 C

F: force on the charge = 2.5*10^-4N

You replace the values of q and F in the equation for E:

hence, the magnitude of the electric field at the position of the carge is 0.5N/C

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electrical power