A 7.12 μC charge is moving at the speed of light in a magnetic field of 4.02 mT. What is the force on the charge?

858.7 N

Explanation:

The magnetic force on the charge F = Bqv where B = magnetic field strength = 4.02 mT = 4.02 × 10⁻³ T, q = charge = 7.12 μC = 7.12 × 10⁻⁶ C and v = c = speed of light = 3 × 10⁸ m/s

F = Bqc

=  4.02 × 10⁻³ T × 7.12 × 10⁻⁶ C × 3 × 10⁸ m/s

= 858.7 N

it becomes positively charged by charging it

f is prop to m1xm2 double m1 double force