Please Help! T = 2π√*(l/g) T = period, l = length and g = acceleration due to gravity

g = 9.80 m/s2 on Earth, gJupiter = 24.6 m/s2 on Jupiter

Using the formula above, algebraically solve for 1.

Step 1: Divide both sides by 2π T/2π = √l/g

Step 2: Square both sides T2/4π2 = l/g

Step 3: Multiply both sides g gT2/4π2 = l

How long does the string need to be if I want to make a period of one oscillation per second? What about on Jupiter?

(8%) problem 12. a bowling ball of mass mb 3 kg 's rolled down the lane with a velocity ofy-2/ m s lt strikes a single remaining pin mp 0.93 kg head on. after the collision the bowling ball has a velocity (in the same direction) of v2 1.1 m/s. = ▲ 33% part (a) write an expression for the velocity of pin in the horizontal direction after the impact, im ,, 33% part (b) what is the pins speed in ms? 33% part (c) assuming the coefficient of friction s μ,-0.1. how far in meters could the pin slide before stopping if it doesn't topple?