Las ruedas de una locomotora de 500 toneladas tiene un coeficiente de friccion estatico con las vias de 0.15 ¿Cual es la fuerza de traccion tangencial maxima ejercida entre las vias y las ruedas?

Ff = 7.35*10^5 N

Explanation:

To find the maximum transverse pulling force you use the following formula, for the friction force:

(1)

μ: friction coefficient = 0.15

N: normal force, which is equal to the weight over the wheel

M: mass of th train = 500 ton = 500 000 kg

g: gravitational acceleration = 9.8 m/s^2

You replace the values of the variables in the equation (1):

hence, the maximum transverse pulling force is 7.35*10^5 N

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