A stone is thrown in the upwards direction at the velocity of 4 m/s. It attains a certain height and then it falls back. During its motion, it experienced an acceleration of 10 m/s2 in the downward direction. What is the maximum height it attained before falling back? *

t

Explanation:Let u be the initial velocity and h be the maximum height attained by the stone.

v

1

2

​

=u

2

−2gh,

(10)

2

=u

2

−2×10×

2

h

​

100=u

2

−10h (i)

Again at height h,

v

2

2

​

=u

2

−2gh

(0)

2

=u

2

−2×10×h

u

2

=20h ... (ii)

So, from Eqs. (i) and (ii) we have

100=10h

h=10m

because growing process had stoped after 4-5 year

answer; how far out of place which the object finished relative to the starting location;