A body covers 24 m in the 6th second and 32 m in the 8th second of its motion. If the body is uniformly accelerated, the distance traveled in the 10th second will be:

The distance covered in the 10th second is 40 m

Explanation:

The parameters given are;

Distance traveled in the 6th second = 24 m

Distance traveled in the 8th second = 32 m

Therefore, we have;

v² = u² + 2·a·s

s = u·t + 1/2·a·t²

Where:

s = Distance traveled

t = Time taken = 1 second each

a = Acceleration

Plugging in the values, we obtain the following equations;

24 = u₆ × 1 + 1/2 × a × 1² = u₆ + a/2.....(1)

Also, 32 = u₈ + a/2

However, in the 8th second, the initial speed is given as follows;

u₈ = u₆ + a×t = u + a × (t₂ - t₁) = u₆ + a × (8 - 6) = u₆ + 2·a

Therefore, we have;

32 = u₆ + 2·a + a/2  

....................(2)

Subtracting equation (1) from equation (2), we have;

∴ 2·a = 8

a = 8/2 = 4 m/s²

The velocity in the 8th second is given as follows;

32 = u₈ + a/2

32 = u₈ + 4/2

u₈ = 32 - 2 = 30 m/s

The velocity in the 10th second is therefore, given as follows;

u₁₀ = u₈ + a×t = u₈ + a × (t₂ - t₁) = u₈ + a × (8 - 6) = u₈ + 2·a = 30 + 2×4 = 38 m/s

The distance covered in the 10th second is therefore given as follows

s₁₀ = u₁₀ + a/2 = 38 + 4/2 = 40 m.

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.

your answer is c! hope this : )