Help with question 19 please

4.2m/s

Explanation:

Now the velocity or speed initiated by the 200g mass at 7.0m/s is related by the formula;

V=ω×r ; ω is the angular velocity

r is the distance

Note that;

ω = √k/m. ; where K is the Force constant of the spring.

m is the mass

We see from the two expressions that v will only change with r if the spring constant and mass stays the same.

Hence we can rewrite the equation of v for two pairs of velocity V1 , V2 and distance r1 , r2 as;

V1/r1 = V2/R2

If V1=7.0m/s , r1=25cm= 0.25m

V2=? r2 = 15cm = 0.15m

Hence we can calculate V2 and is;

V2 = V1 × R2/ R1

V2 = 7 × 0.15 / 0.25= 4.2m/s

i think its c if i'm wrong

part 1: which substance has a higher solubility?

a

smallest amount left undissolved atall temps in table shown most has dissolved high sol'by