2. A certain rigid aluminum container contains a liquid at a gauge pressure of P0 = 2.02 × 105 Pa at sea level where the atmospheric pressure is Pa = 1.01 × 105 Pa. The volume of the container is V0 = 4.55 × 10-4 m3. The maximum difference between the pressure inside and outside that this particular container can withstand before bursting or imploding is ΔPmax = 2.68 × 105 Pa. For this problem, assume that the density of air maintains a constant value of rhoa = 1.20 kg / m3 and that the density of seawater maintains a constant value of rhos = 1025 kg / m3. A) The container is taken from sea level, where the pressure of air is Pa = 1.01 10 Pa, to a higher altitude. What is the maximum height h in meters above the ground that the container can be lifted before bursting?
B) If we include the decrease in the density of the air with increasing altitude, what will happen?
C) If the container were not rigid, its volume would increase as it is lifted to greater altitudes.
D) The depth below the surface of the ocean the container can reach before imploding is less than the altitude in the atmosphere the container can reach before exploding.
E) What is the maximum depth h in meters below the surface of the ocean that the container can be taken before imploding?
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