The force exerted by the wind on the sails of a sailboat is Fsail = 330 N north. The water exerts a force of Fkeel = 210 N east. If the boat (including its crew) has a mass of 260 kg, what are the magnitude and direction of its acceleration? magnitude m/s2 direction ° north of east

The magnitude of the acceleration is

The direction is   north of  east

Explanation:

From the question we are told that

   The force exerted by the wind is  

   The force exerted by water is  

      The mass of the boat(+ crew) is  

Now Force is mathematically represented as

Now the acceleration towards the north is mathematically represented as

substituting values

Now the acceleration towards the east is mathematically represented as

substituting values

The resultant acceleration is  

substituting values

The direction with reference from the north is evaluated as

Apply SOHCAHTOA

substituting values

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.