4) Un péndulo tiene un período de oscilación de 4 seg (T) , realizando su movimiento desde su posición de equilibrio, si la aplitud del movimiento es de

10 cm y el ángulo de desfase es de 20 grados. Calcular:

La posición en la que se encuentra a los 5 segundos de haber iniciado el

movimiento.

x = 1.43 cm

Explanation:

The horizontal displacement of the pendulum can be found using the following equation:

Where:

x₀: is the initial horizontal displacement = 10 cm

ω: is the angular frequency

t: is the time = 5 s

Φ: is the phase shift = 20° = 20*2π/360 = 0.35 rad        

The angular frequency can be calculated using the oscillation perid (T):

The horizontal displacement is:

Therefore, the displacement of the pendulum at 5 s is 1.43 cm.

I hope it helps you!

r=rho l/a where a is the area, l is the length and rho is resistivity so the greater the area the lesser the resistance thats why the earth pin is thicker bcos current follow the shortest path, so less resistive .

i think the answer is a, hope this : )