An engine performs 17,640 J of work on a scooter. The scooter and riderhave a combined mass of 180 kg. If the scooter started at rest, what is the speed of the bike after the work is performed?

  14 m/s

Explanation:

We assume that all of the work performed is translated to kinetic energy:

  KE = 1/2mv² . . . . m represents mass

  v = √(2KE/m) . . . . m represents mass

  = √(2(17,640J/180 kg)) = √(196 m²/s²) . . . . m represents meters

  v = 14 m/s

The speed of the bike is about 14 meters per second.

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.