A force acting on a body of mass 200g displace it through 200cm in 5s. Find the magnitude of the force if the initial velocity of is Zero

F = 0.32 N

Explanation:

GIVEN:

Mass = m =  200 g = 0.2 kg

Distance = S = 200 cm = 2 m

Time = t = 5 s

Initial velocity = U = 0 m/s

REQUIRED

Force = F = ?

SOLUTION

Using Second Equation of Motion,

S = Ut + 1/2 at²

2 = (0)(5) + 1/2 a(5)²

2 = 25/2 a

a = 4/25

a = 0.16 m/s²

So,

Acceleration = a = 0.16 m/s²

Now Using Equation from Newtons Second Law of Motion

F = ma

F = (2)(0.16)

F = 0.32 N

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