When air expands adiabatically (without gaining or losing heat), its pressure P P and volume V V are related by the equation P V 1.4 = C PV1.4=C, where C C is a constant. Suppose that at a certain instant the volume is 450 cm 3 450 cm3 and the pressure is 80 kPa 80 kPa and is decreasing at a rate of 10 kPa/min 10 kPa/min. At what rate is the volume increasing at this instant? (Round your answer to the nearest whole number.)

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Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.