Two cars collide with each other. Before the collision, one car (m = 1100 kg) is going north at 18 m/s and the other car (m= 1300 kg) is going south at 16
m/s. What is the momentum of the system made up of the two cars after the
collision?
A. 40,600 kg•m/s north
B. 1000 kg•m/s south
C. 40,600 kg. m/s south
D. 1000 kg•m/s north

B

Explanation:

In collision, whether elastic or inelastic collisions, momentum is always conserved. That is, the momentum before collision will be equal to the momentum after collision.

Since momentum is a vector quantity, the direction will also be considered.

Momentum = MV - mU

Let

M = 1100 kg is going north

at V = 18 m/s and the other car

m= 1300 kg is going south

at U = 16m/s.

Substitute all the parameters into the formula

Momentum = (1100 × 18) - (1300 × 16)

= 19800 - 20800

= - 1000

It's due south since the final answer is negative.

= 1000 kgm/s due south.

Therefore, the momentum of the system of the two cars after the

collision is 1000 kgm/s due south

atomic = no of protons.

mass number-atomic number = neutron number

muscle endurance

explanation:

i can do 50 in a row ( but i get so tired after that)