A 120 kg quarterback is stationary in the "pocket" and hit by a defensive tackle with 4000 Newtons of force. What acceleration did the quarterback experience after being hit

33.3 m/s^2

Explanation:

Here we need to use the second Newton's law.

F = m*a

Force equals mass times the acceleration.

Here we know that the force is F = 4000 N, and the mass is 120kg, then the acceleration must be:

4000 N = 120kg* a

a = (4000/120) m/s^2 = 33.3 m/s^2

explanation:

considering the bohr theory, the type of connection that requires the transfer the answer conuldn't be right

more than, less

less than, more