A stone is dropped from a tower of height 3600cm. Find the velocity by which it strike the ground. Find the time taken to reach the ground.

1. 26.56m/s.

2. 2.71 secs.

Explanation:

The following data were obtained from the question:

Height (h) = 3600cm

Velocity (v) =..?

Time (t) =..?

Next, we shall convert the height, 36000cm to metre (m). This is illustrated below:

100cm = 1m

Therefore, 3600cm = 3600/100 = 36 m

Therefore, the height is 36m.

1. Determination of the velocity with which the stone struck the ground. This is illustrated below:

Acceleration due to gravity (g) = 9.8m/s²

Height (h) = 36m

Velocity (v) =.?

v² = 2gh

v² = 2 x 9.8 x 36

v² = 705.6

Take the square root of both side.

v = √705.6

v = 26.56m/s

Therefore, the velocity with which the stone struck the ground is 26.56m/s.

2. Determination of the time taken for the stone to reach the ground.

Height (h) = 36m

Acceleration due to gravity (g) = 9.8m/s²

Time (t) =.?

t = √(2h/g)

t = √(2 x 36/ 9.8)

t = √(72/9.8)

t = 2.71 secs

Therefore, the time taken for the stone to reach the ground is 2.71 secs

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y