A daredevil is attempting to jump his motorcycle over a line of buses parked end to end by driving up a 30 degree ramp at a speed of 43m/s. How many buses can he clear if the top of the takeoff ramp is at the same height as the bus tops and the buses are 20.0m long?

No. of Cars = 8

Explanation:

In order to find the no. of buses that can be cleared by the daredevil, we first need to find the distance he will cover during its motion. Since, the motion is projectile, therefore, the horizontal distance will be equal to range of the projectile:

R = V² Sin 2θ/g

where,

R = Range = ?

V = launch speed = 43 m/s

θ = angle with horizontal = 30°

g = 9.8 m/s²

Therefore,

R = (43 m/s)² Sin 60°/(9.8 m/s²)

R = 163.4 m

Now, for the number of cars cleared, we use the following formula:

No. of Cars = R/Length of single bus

No. of Cars = 163.4 m/20 m

No. of Cars = 8.17

No. of Cars = 8

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.

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