A charge of 4.5 × 10-9 C is located 3.2 m from a charge of -2.8 × 10-9 C. Find the electrostatic force exerted by one charge on the other.

F = 1.1074 × N

Explanation:

An electrostatic force is either a force or attraction or repulsion between two charges. It can be determined by:

F =

where: F is the force, k is a constant, is the first charge, is the second charge and r the distance between the charges.

Given that: k = 9 × N, = 4.5 × C, = -2.8 × C and r = 3.2 m.

Then,

F =

 =

 = 1.1074 ×

The electrostatic force exerted is 1.1074 × N, and it is a force of attraction.

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

massxgravity x heght=weightxheight= pe

4900=490xh

h=10