A driver moves with initial velocity of 40m/s accelerates uniformly at a rate of 12m/s2.  It attains a velocity 52m/s. calculate the distance covered during the journey.

distance=46m

Explanation:

initial velocity(u)=40m/s

final velocity(v)=52m/s

acceleration=12m/s²

distance(s)=?

v²=u²+2as (using equ.of motion)

(52)²=(40)²+2(12)s

2704=1600+24s

24s=2704-1600

24s=1104

s=1104/24

s=46m

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm

earth's neighboring galaxy, the andromeda galaxy, is a distance of 2.54×107 light-years from earth. if the lifetime of a human is taken to be 70.0 years, a spaceship would need to achieve some minimum speed min to deliver a living human being to this galaxy.