A weight lifter lifts a 300-N set of weights from ground level to a position over his head, a vertical distance of 2.15 m. How much work does the weight lifter do, assuming he moves the weights at constant speed

W = 645 J

Explanation:

The work done on an object is equal to the product of the force applied on the object and the distance through which it moves.

W = F d

where,

W = Work Done

F = Force

d = Displacement

In this case, the variables are as follows:

F = Weight  of Sets = 300 N

d = vertical distance covered = 2.15 m

Therefore,

W = (300 N)(2.15 m)

W = 645 J

  the unit of the measure =

explanation:

  the property that is quantified by the energy needed per of material to raise the temperature by one.

  si unit of energy = joule (j)

  si unit of temperature = kelvin (k)

  si unit of mass of material = kilogram (kg)

the property that is quantified by the energy needed per of material to raise the temperature by one is called specific heat.

the unit of specific heat is

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