A magnetic field exerts a force of 0.25 N on an 8.0 cm length of wire carrying a current of 3.0 A at right angles to the field. Calculate the force that the same field would exert on another wire 20 cm long carrying the same current. I WILL GIVE

0.625N

Explanation:

Given the following:

Magnetic field Force = 0.25N

Length of wire = 8cm

Current = 3.0 ampere

The force that the same field will exert on another wire 20cm long carrying the same current will be :

Since current 'I' is the same ;

0.25 Force = 8cm

x force = 20cm

Cross multiply:

8x = (20 × 0.25)

x = (20 × 0.25) / 8

x = 5 / 8

x = 0.625

Force = 0.625N

ι вєℓιєνє ιт ιѕ тнє fιяѕт ¢нσι¢є(α.)

нє ѕнσυℓ∂ ѕмιℓє ρσℓιтℓу αи∂ ѕρєαк тσ тнє ρєяѕσи ωнσ ιѕ ιитєяяυριиg αfтєя тнє ∂ιѕ¢υѕѕισи

нσρє ι ¢συℓ∂ нєℓρ.

where’s the list ? the question is incomplete