A fast pitch softball player does a "windmill" pitch moving her hand through a vertical circular arc to pitch a ball at 71mph. The 0.20 kg ball is 53 cm from the pivot point at her shoulder. Just before the ball leaves her hand, what is its centripetal acceleration?

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If its history of, then b) because a) implies only present day (now)

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j