When a hydrometer (see Fig. 2) having a stem diameter of 0.30 in. is placed in water, the stem protrudes 3.15 in. above the water surface. If the water is replaced with a liquid having a specific gravity of 1.10, how much of the stem would protrude above the liquid surface

5.79 in

Explanation:

We are given that

Diameter,d=0.30 in

Radius,r=

Weight of hydrometer,W=0.042 lb

Specific gravity(SG)=1.10

Height of stem from the water surface=3.15 in

Density of water=

In water

Volume  of water displaced

Volume of another liquid displaced=

Change in volume=V-V'

Substitute the values

By using

1 ft=12 in

l=2.64 in

Total height=h+l=3.15+2.64=5.79 in

Hence, the height of the stem protrude above the liquid surface=5.79 in

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